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    "The Newton polynomial can be expressed in a simplified form when $ x_0,x_1,...,x_k $ are arranged consecutively with equal spacing. Introducing the notation $h=x_{i+1} - x_i$ for each $ i = 0, 1,...,k-1$ and $ x = x_0+sh$, the difference $x-x_i$ can be written as $(s-i)h$. So the Newton polynomial becomes $$\\sum_{i=0}^k = {s \\choose i}i!h^i[y_0,...,y_i]. $$This is called the Newton forward divided difference formula."
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "Let's check this method for the next function: $$f(x*3^x)$$ with $\\varepsilon = 0.0001$"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {},
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "f(x 0 ) = -0.3333333333333333\n",
      "f(x 1 ) = -0.28867513459481287\n",
      "f(x 2 ) = 0.0\n",
      "f(x 3 ) = 0.8660254037844386\n",
      "f(x 4 ) = 3.0\n",
      "[-0.33333333  0.0446582   0.24401694  0.33333333  0.35726559]\n",
      "Count of parts in the interpolation formula: 5\n",
      "Value of functions f(x) in -0.25 = -0.06957804087824197\n"
     ]
    }
   ],
   "source": [
    "import numpy as np \n",
    "import math\n",
    "x = np.array([-1.0, -0.5, 0, 0.5, 1.0], float)\n",
    "y = np.array([-0.3333333333333333,-0.28867513459481287, 0.0, 0.8660254037844386, 3.0], float)\n",
    "eps = 0.0001\n",
    "n = len(x)\n",
    "\n",
    "for i in range(n):\n",
    "    a = float(x[i]*(3**x[i]))\n",
    "    print(\"f(x\",i,\") =\",a)\n",
    "\n",
    "def coef(x, y): \n",
    "    x.astype(float) \n",
    "    y.astype(float) \n",
    "    n = len(x) \n",
    "    a = [] \n",
    "    for i in range(n): \n",
    "        a.append(y[i]) \n",
    "    for j in range(1, n): \n",
    "        for i in range(n-1, j-1, -1): \n",
    "            a[i] = float(a[i]-a[i-1])\n",
    "    return np.array(a)  \n",
    "print(coef(x, y))\n",
    "r = float(-0.25)\n",
    "t = float((r - x[0])/(x[1]-x[0]))\n",
    "\n",
    "def tsum(t, n):\n",
    "    sum = float(1.0)\n",
    "    for i in range(0, n, 1):\n",
    "        sum = float(sum*(t-i))\n",
    "    return float(sum)\n",
    "    \n",
    "def Eval(a, x, t): \n",
    "    x.astype(float) \n",
    "    n = len(a) \n",
    "    temp = a[0]\n",
    "    count = 1\n",
    "    for i in range(1, n, 1):\n",
    "        temp += (tsum(t, i-1)*a[i])/math.factorial(i)\n",
    "        count = count + 1\n",
    "    print(\"Count of parts in the interpolation formula:\",count)\n",
    "    return temp\n",
    "result = Eval(coef(x,y),x,t)\n",
    "\n",
    "print(\"Value of functions f(x) in\",r,\"=\",result)\n"
   ]
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   "cell_type": "code",
   "execution_count": null,
   "metadata": {},
   "outputs": [],
   "source": []
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